-12x^2-196=-112x

Solution for -12x^2-196=-112x equation:

-12x^2-196=-112x

We move all terms to the left:

-12x^2-196-(-112x)=0

We get rid of parentheses

-12x^2+112x-196=0

a = -12; b = 112; c = -196;
Δ = b2-4ac
Δ = 1122-4·(-12)·(-196)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-56}{2*-12}=\frac{-168}{-24}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+56}{2*-12}=\frac{-56}{-24}
=2+1/3
$